Objective
Today we will expand our knowledge of strings, combining it with what we have already learned about loops. Check out the Tutorial tab for learning materials and an instructional video.
Task
Given a string, S , of length N that is indexed from 0 to N - 1, print its even-indexed and odd-indexed characters as 2 space-separated strings on a single line (see the Sample below for more detail).
Note: 0 is considered to be an even index.
Example
s = adbecf
Print abc def
Input Format
The first line contains an integer, T (the number of test cases).
Each line i of the T subsequent lines contain a string, S.
Constraints
Output Format
For each String S(j) (where 0 <= j <= T - 1), print S(j)'s even-indexed characters, followed by a space, followed by S(j)'s odd-indexed characters.
Sample Input
2
Hacker
Rank
Sample Output
Hce akr
Rn ak
Explanation
Test Case 0: S = "Hacker"
S[0] = "H"
S[1] = "a"
S[2] = "c"
S[3] = "k"
S[4] = "e"
S[5] = "r"
The even indices are 0, 2, and 4, and the odd indices are 1, 3, and 5. We then print a single line of 2 space-separated strings; the first string contains the ordered characters from S's even indices (Hce), and the second string contains the ordered characters from S's odd indices (ark).
Test Case 1: S = "Rank"
S[0] = "R"
S[1] = "a"
S[2] = "n"
S[3] = "k"
The even indices are 0 and 2, and the odd indices are 1 and 3. We then print a single line of 2 space-separated strings; the first string contains the ordered characters from S's even indices (Rn), and the second string contains the ordered characters from S's odd indices (ak).
import java.io.*;
import java.util.*;
public class Solution {
public static void main(String[] args) {
/* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
Scanner sc = new Scanner(System.in);
int T = sc.nextInt();
sc.nextLine();
for(int i=0; i<T; i++) {
String S = sc.nextLine();
String odd = "";
String even = "";
for(int j=0; j<S.length(); j++) {
if(j%2 == 0) {
even += S.charAt(j);
} else {
odd += S.charAt(j);
}
}
System.out.println(even + " " + odd);
}
}
}
[Hackerrank] Dictionaries and Maps (0) | 2021.10.05 |
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[Hackerrank] Arrays (0) | 2021.10.02 |
[Hackerrank] Loops (0) | 2021.09.29 |
[Hackerrank] Class vs. Instance (0) | 2021.09.27 |
[Hackerrank] Intro to Conditional Statements (0) | 2021.09.26 |